Note that any time the desired_func function (or any other function whose signature doesn't match the funcp function pointer) needs to be called through the function pointer, the function pointer will have to be cast back to its original type ( void (*)(my_type*) in this case) before calling the function, or it invokes undefined behavior. For example : init(5, (void (*)(void*)) desired_func) so Im trying to pass a type double to a function that accepts void as one of the parameters. case is introduced, it may be inconsistent with mathematical standards. different parameter types), you can add explicit casts. (sems(s)) Upointers(sems(s)), which seems to be the most natural generalization. Hitachi u pointer software download, Cs lewis the shortest way home dvd. If you want to be able to use functions with different signatures (eg. hire holywell bay, He hierarchy of the type sampleview is inconsistent. On the line in the init function above: my_struct_t *my_str Ĭhange the function pointer types to match the function, ie. The answer is, int size (see note at the bottom) and int are definitely not the same type. Incompatible pointer types assigning to 'void (*)(void *)' from My call to the init func: init(5, desired_func) Init function: my_struct_t *init(int num, void (*my_funcp)(void *data)) free()) but not when I use it with the test_func function below. The code seems to compile when I use it with a default function (i.e. My code is below, but basically what I'm doing is storing a function pointer in a struct, and initializing the struct in another function that I call from my main. I'm having getting the above warning and understand it, but just don't know how to fix it.
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